Thursday, 24 November 2016

COMMON NUMBER SET

Common Number Sets
There are sets of numbers that are used so often that they have special names and symbols:
Symbol
Description
http://www.mathsisfun.com/images/symbols/set-natural-lg.gif
Natural Numbers
The whole numbers from 1 upwards. (Or from 0 upwards in some fields of mathematics). Read More ->
The set is {1,2,3,...} or {0,1,2,3,...}
http://www.mathsisfun.com/images/symbols/set-integer-lg.gif
Integers
The whole numbers, {1,2,3,...} negative whole numbers {..., -3,-2,-1} and zero {0}. So the set is {..., -3, -2, -1, 0, 1, 2, 3, ...}

http://www.mathsisfun.com/images/number-line.gif
(is for the German "Zahlen", meaning numbers, because I is used for the set of imaginary numbers). Read More ->
http://www.mathsisfun.com/images/symbols/set-rational-lg.gif
Rational Numbers
The numbers you can make by dividing one integer by another (but not dividing by zero). In other words fractionsRead More ->
Q is for "quotient" (because R is used for the set of real numbers).
Examples: 3/2 (=1.5), 8/4 (=2), 136/100 (=1.36), -1/1000 (=-0.001)
(Q is for the Italian "Quoziente" meaning Quotient, the result of dividing one number by another.)

Irrational Numbers
Any real number that is not a Rational Number. Read More ->
http://www.mathsisfun.com/images/symbols/set-algebraic-lg.gif
Algebraic Numbers
Any number that is a solution to a polynomial equation with rational coefficients.
Includes all Rational Numbers, and some Irrational Numbers. Read More ->

Transcendental Numbers
Any number that is not an Algebraic Number
Examples of transcendental numbers include π and eRead More ->
http://www.mathsisfun.com/images/symbols/set-real-lg.gif
Real Numbers
All Rational and Irrational numbers. They can also be positive, negative or zero.
Includes the Algebraic Numbers and Transcendental Numbers.
A simple way to think about the Real Numbers is: any point anywhere on the number line (not just the whole numbers).
Examples: 1.5, -12.3, 99, √2, π
They are called "Real" numbers because they are not Imaginary Numbers. Read More ->
http://www.mathsisfun.com/images/symbols/set-imaginary-lg.gif
Imaginary Numbers
Numbers that when squared give a negative result.
If you square a real number you always get a positive, or zero, result. For example 2×2=4, and (-2)×(-2)=4 also, so "imaginary" numbers can seem impossible, but they are still useful!
Examples: √(-9) (=3i), 6i, -5.2i
The "unit" imaginary numbers is √(-1) (the square root of minus one), and its symbol is i, or sometimes j.
i2 = -1
http://www.mathsisfun.com/images/symbols/set-complex-lg.gif
Complex Numbers
A combination of a real and an imaginary number in the form a + bi, where a andb are real, and i is imaginary.
The values a and b can be zero, so the set of real numbers and the set of imaginary numbers are subsets of the set of complex numbers.
Examples: 1 + i, 2 - 6i, -5.2i, 4





Illustration
Natural numbers are a subset of Integers
Integers are a subset of Rational Numbers
Rational Numbers are a subset of the Real Numbers
Combinations of Real and Imaginary numbers make up the Complex Numbers.

Thursday, 17 November 2016

Divisibility Tests

Divisibility Tests

Stage: 3, 4 and 5
Article by Tim Rowland
Published January 1997,October 2010,February 2011.

Multiples of 2 and 5

The easiest divisibility tests are for 2 and 5. A number is divisible by 2 if its last digit is even, by 5 if its last digit is 0 or 5.
(In this article 'number' will always mean 'positive whole number')
These tests refer to 'digits' in the (usual) base 10 representation of the number, so that (for example) 2645 represents the number (5×1)+(4×10)+(6×100)+(2×1000). The tests for 2 and 5 work because the rest of the number (apart from the last digit) is a multiple of 10, and so is always divisible by 2 and 5. If the last digit is a multiple of 2 (or 5), then the whole number must be.

Multiples of 4 and 8

Since 1001000 and so on are multiples of 4, it follows (as for 2) that a number is divisible by 4if the number represented by its last two digits is a multiple of 4.
Example: 3728 is divisible by 4 because 28 is.
Powers of 10, from 1000 on, are divisible by 8, therefore it follows that a number is divisible by 8 if the number represented by its last three digits is a multiple of 8.
Example: 3728 is divisible by 8 because 728 is.
Note: if you think that you need a calculator to decide whether (for example) 728 is divisible by 8, then it will help you to learn the 8 times table and to practice some divisions which you can check on your calculator until you are confident that you can divide by 8 and don't need the calculator.

Multiples of 3 and 9

A slightly more complicated version of such reasoning gives rise to a test for divisibility by 3.
Now 10 is (3×3)+1, so (for example) 50 is (15×3)+5. To decide whether 57 is divisible by 3, we can take out the 15 lots of 3 in 57 and just check whether the remaining 5+7 is divisibly by 3: which it is, since 5+7=12.
Put slightly differently, we reason that 57=(a multiple of 3)+(5+7).
Therefore 57 is a multiple of 3 if and only if 12 is.
For 257, we note that 100 is (33×3)+1, so 200=(66×3)+2. We looked at 57 above.
Therefore 257=(a multiple of 3)+(2+5+7).
Once again, 257 is a multiple of 3 if and only if the sum of its digits is a multiple of 3.
Actually, that sum is 14, which is a multiple of 3 if and only if 1+4 is.
Since 5 is not a multiple of 3, neither is 257.
In general, 10=9+1100=99+11000=999+1 and so on:
every 'power' of 10 (like 10100100010000 and so on) is just 1 more than a multiple of 3, and so the method for divisibility can be applied to a number with any number of digits.
Example: is 1997 divisible by 3?
Now 1+9+9+7=26, and 2+6=8 which is not divisible by 3.
Therefore 1997 is not divisible by 3.
Note: in this example, we added the digits of 1997, then we added the digits of the answer, and so on, until we arrived at an answer with just one digit, sometimes called the 'digital root' of the original number. So we can say that a number is divisible by 3 if and only if its digital root is 36 or 9.
Because 10=9+1100=99+11000=999+1 and so on, we can see that every power of 10 is just 1 more than a multiple of 9, and so the method for divisibility by 3 actually transfers to 9 too: a number is divisible by 9 if and only if its digital root is 9.

Multiples of 6 and 12

A number is divisible by 6 if and only if it is divisible by both 2 and 3.
This is not at all obvious: it is true because 2×3=6 and because 2 and 3 are 'coprime' - i.e. they have no common factor (apart from 1).
Example: 1638 is even and its digital root is 9. Therefore it is a multiple of 6.
Similarly, a number is divisible by 12 if and only if it is divisible by both 3 and 4 - because 3×4=12, and 3 and 4 are coprime.

Multiples of 11

The test for 11 is a modified version of that for 3 and 9.
Whereas every power of 10 is 1 more than a multiple of 3 (or 9), an alternating pattern emerges for multiples of 11. That is to say, 10 is 1 less than 11100 is 1 more than 9×111000 is 1 less than 91×1110000 is 1 more than 909×11, and so on. If we write `m11' as shorthand for 'a multiple of 11', we see that odd powers of 10 are m111, and even powers of 10 are m11+1.

Example:
Is 54637 divisible by 11?
Solution: Start with the units digit and work 'left':
54637=7+3×(m111)+6×(m11+1)+4×(m111)+5×(m11+1),
which equals m11+(73+64+5) or m11+11. Therefore 54637 must be a multiple of 11.
This is only slightly more complicated than finding the digital root of a number, because we alternately add and subtract the digits, starting from the right. (We could call the answer the 'alternating digital root').
Example:

What is the remainder when 7107 is divided by 11?
Solution:
7107=282475242 whose alternating digital root is 24+25+74+28+2=6. Our number is 6 less than a multiple of 11, so if we divide it by 11, the remainder will be 5.
A number is divisible by 11 if its alternating digital root is 0 or 11 (or any other multiple of 11).